DS POINTER
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related to pointers in C programming. Here's a brief explanation and the
corrected versions of the code examples you provided:
Understanding Pointers in C
Code Example 1: Basic Pointer Usage
#include <stdio.h>
{
int a = 5;
int *b;
b = &a;
printf("value
of a = %d\n", a);
printf("value
of a using address of a = %d\n", *(&a));
printf("value
of a using pointer b = %d\n", *b);
printf("address of a = %p\n", (void*)&a);
printf("address stored in pointer b = %p\n", (void*)b);
printf("address of pointer b = %p\n", (void*)&b);
printf("value
of b = address of a = %p\n", (void*)b);
return 0;
}
Output Explanation:
The `value of a` lines confirm that dereferencing `b` gives
the value stored in `a`.
The `address of a` and `address stored in pointer b` should
match because `b` holds the address of `a`.
The `address of pointer b` is different because it's the
location where `b` itself is stored.
Code Example 2: Pointer to Pointer
#include <stdio.h>
{
int a = 5;
int *b;
int **c;
b = &a;
c = &b;
printf("value
of a = %d\n", a);
printf("value
of a using pointer b = %d\n", *b);
printf("value
of a using pointer c = %d\n", **c);
printf("address of a = %p\n", (void*)&a);
printf("address stored in pointer b = %p\n", (void*)b);
printf("address stored in pointer c (address of b) = %p\n",
(void*)c);
printf("address of b = %p\n", (void*)&b);
printf("address of c = %p\n", (void*)&c);
return 0;
}
Output Explanation:
‘c` gives the value stored in `a` because `c` points to `b`,
and `b` points to `a`.
The addresses printed show the relationships between `a`,
`b`, and `c`.
Key Concepts:
- Pointer Arithmetic: The ability to manipulate the memory address stored in a pointer by using arithmetic operations.
These examples illustrate how pointers work in C, providing
the foundation for more complex data structures and memory management
techniques.